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On Thu, Oct 11, 2012 at 2:35 PM, John E Clifford <kali9putra@hidden.email> wrote: > > The third possibility, > conjugation, would have the predicate marked in some way at each place > picking which of the available terms was to fill that place. From what I could gather (but I may be completely wrong), Livagian does something like that. So to say "everyone's mother loves them" you could say c1-Everyone(c2-Mother(Loves))), where c1 and c2 are conjugations such that c2 indicates that the x1 of Mother and the x1 of Love are the same and that those two co-referring places are bound, and also that the x2 of Mother and the x2 of Love are the same, and that those other two co-referring places are (at this stage) unbound. c1 says that the x1 of Everyone and the x1 of c2-Mother(Love) are co-referring and bound. So you need one conjugation for each possible combination of joined places, and different sets of conjugations in case the places are bound or remain unbound by the join. "everyone loves their mother" would be the same except instead of c2 you would conjugate with c3, which makes x1 of Mother co-refer with x2 of Love (and bound) and x2 of Mother co-refer with x1 of Love (and unbound). co ma'a xrxe