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On Mon, Oct 8, 2012 at 8:32 PM, And Rosta <and.rosta@hidden.email> wrote: > > My version: > Binder, with two complements, binding a bindee, which is generally an > argument-place complement (tho not in case of jek, ji'uk). The binding > relation is expressed in the phonological form of the binder and the > argument-place. > > Your version (if I understood right, which I probably didn't): > Binder has three complements, one of which is a variable. It generally > binds complements of predicates; complements of predicates are variables. > The variable has multiple forms, all of the same shape; each form cliticizes > to the form of the syntactic word the variable is a complement of. > Syntactically it's one entity, but phonologically it gets expressed as many > different forms, of the same shape. My version would be: Binder has two complements (each one a formula), and it binds zero or more variables of its complements. Variables are not syntactic objects by themselves (they are not words). Which variables a formula has, and which variables a binder binds, is determined by the phonological form of the syntactic objects. An atomic formula is a word and has one or more free variables (and no bound variables). An operator may add to, remove (i.e. bind) or leave unchanged the free variables of its complement formula(s). Which of those things it does depends on which operator it is. For example "fV" will add (mormally one) free variable to those of its complement formula, "na" will neither add nor remove any free variables from its complement formula, "rV" will remove (bind) any free variable(s) from its complement formulas that coincide with the variables expressed in its phonological form. So the formula resulting after the application of an operator can have more, fewer or the same number of free variables as the operator's complement formula(s). Variables bound within the complement(s) of an operator are invisible to the operator and are unaffected by it. co ma'a xrxe