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On Tue, Jan 14, 2003 at 08:23:39PM -0600, Jordan DeLong wrote:
> On Tue, Jan 14, 2003 at 07:11:55PM -0600, Jordan DeLong wrote:
> [...]
> > However, sets *are* possible values of variables in Quine[1]... So
> > I still don't know what you mean.
> >
> > [1] Wee, something I can actually proove (using '<' as
> > containment again):
> > |- (x)(x = x) (theorem 182)
> > |- V < V (theorem 210)
> > |- V = x^(x = x) (definition of V)
> > |- V < x^(x = x) (subst of equivalents)
> > |- Ey(V < y . (x)(x < y -> x = x)) (def of abstraction)
> > |- Ex(x = V)
>
> Doh this is wrong.
>
> I confused membership and containment in the 5th line. I'll try
> again later.
Ok it's still correct though; I was just thinking member when typing
<.
|- (x)(x = x) (theorem 182)
|- V e V (theorem 210)
|- V = x^(x = x) (definition of V)
|- V e x^(x = x) (subst of equivalents)
|- Ey(V e y . (x)(x e y -> x = x)) (def of abstraction)
|- Ex(x = V)
--
Jordan DeLong - fracture@hidden.email
lu zo'o loi censa bakni cu terzba le zaltapla poi xagrai li'u
sei la mark. tuen. cusku
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