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Some considerations about LAhE and quantifiers.
1- lu'a an individual/member/component of
CLL does not say anything (that I could find) about default
quantifiers for LAhEs. I won't assume any for now.
I take lu'a to work thus:
ro lu'a ko'a - each member of ko'a
ro lu'a ko'a e ko'e - each member of both ko'a and ko'e
ro lu'a ko'a a ko'e - each member of either ko'a or ko'e or both
{ro lu'a ko'a e ko'e} is equivalent to {ro lu'a ko'a ku'a ko'e},
each member of the intersection of ko'a and ko'e, and {ro lu'a
ko'a a ko'e} is equivalent to {ro lu'a ko'a jo'e ko'e}, each member
of the union of ko'a and ko'e.
{ro lu'a ko'a enai ko'e} is each member of ko'a that is not a
member of ko'e, etc.
Similarly {ro lu'a ro lo broda} is each member of every broda
(i.e. each member of the intersection of all broda) and
{ro lu'a su'o lo broda} is each member of at least one broda,
i.e. each member of the union of all broda. For these to make
sense, brodas have to be things with members.
{su'o da zo'u ro lu'a da} is different from {ro lu'a su'o da}.
The first gives, for some X, each member of X. The second gives
each member of at least some X (i.e. everything).
{ro da zo'u ro lu'a da} is different from {ro lu'a ro da}.
The first is for each X, each member of X. The second
one is each member of every X, (i.e. nothing).
We can expand {PA1 lu'a PA2 da} as {PA1 de poi PA2 da zo'u de cmima da}
2- lu'i a set formed from
Here I'm not so sure. Is {lu'i ko'a} some set that has ko'a
as one of its members, or is it the set that has ko'a as its only
member, or something else?
If we take it to be the reverse of lu'a, we would expand
{PA1 lu'i PA2 da} as {PA1 de poi PA2 da zo'u de se cmima da}.
So {ro lu'i ko'a} would be each set that has ko'a as a member,
not necessarily as its only member. I have no idea whether this
is a useful notion or not. {su'o lu'i ko'a} is some set that
has ko'a as one of its members. {ro lu'i ko'a enai ko'e} would
be each set that has ko'a as a member and does not have ko'e as
member, etc. {ro lu'i ro lo broda} is each set that contains all
broda, {ro lu'i su'o lo broda} is each set that contains at least
some broda.
If we take the complement to be the full list of the members,
we run into trouble with things like {lu'i ko'a enai ko'e}.
How is that different from {lu'i ko'a}? And what is
{lu'i ko'a a ko'e}?
A third possibility is that ko'a itself has members and then
that {lu'i ko'a} is the set whose members are the members of
ko'a. This view has been offered in the past, but I don't
think it is worth defending.
3- lu'o a mass formed from
This one has possibilities analogous to those of lu'i.
So, while {lu'a} seems to be fairly clear, the functioning of
{lu'i} and {lu'o} is not at all clear to me.
mu'o mi'e xorxes
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