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And Rosta scripsit:
> > > > > In other words, {tu'o} erases the boundaries between members
> >
> > That would be black magic
>
> It seems exactly right to me. And you seem to agree above, on condition
> that (as is generally agreed), tu'o is mo'e zi'o.
lo tu'o djacu, fair enough, but lo tu'o prenu would say not "I am not
counting the prenu", but "the prenu cannot be counted (by anyone)",
which is not true.
> If you are referring to part of it, then you are referring to part
> of the whole of it. If you are referring to it, then you are referring
> to the whole of it. The *only* function of {pi ro} is to cancel the
> implicit {pisu'o}; it adds nothing to the meaning, and serves merely
> to block {pisu'o} from being added. If there was a cmavo that just
> meant "do not insert the elliptized cmavo", it would work equally
> well.
I think we agree, but I still find your notation rebarbative, as if
"loi" *by rights* meant "pi ro loi". Why not say that {pi ro loi}
means "pi ro loi", and that {loi} and {pi su'o loi} mean "loi" =
"pi su'o loi"?
> > Ah. I see. You are treating lo as singular(izing) here, which is
> > ultra vires. "lo du be X" is just "lo X"; one is no more singular
> > than the other
>
> "lo du be X" is not just "lo X". If this is not sufficiently obvious
> from "lo du be ro", try "lo du be no" -- "lo du be no broda" means
> "something that is not broda", it does not mean "no broda".
Well, I am wrong but I don't think you are right even so. Let's
unpack:
lo du be no broda cu brode
da poi du be no broda cu brode
da du be no broda .ije da brode
su'o da no de poi broda zo'u (tu'e da du de .ije da broda tu'u)
su'o da naku su'o de poi broda zo'u (tu'e ... tu'u)
Now since da = de, we can say:
su'o da naku su'o da ...
which is a flat contradiction. So "lo du be no broda" doesn't meant
what you think it means, and and in fact doesn't mean anything.
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