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three pairs of shoes & excellent solutions



"Three pairs of shoes" is very difficult to express adequately in Lojban.
"(le) ci lo re mei be (fi) ????" is longwinded & it is hard to see what
can fill x2 or x3 in order to state that the members are shoes, though
LE-Kind cutci would be the best choice.

Xorxes had suggested an ExSol that would allow it to be expressed as
"(LE) ci loi re cutci". I'd like to support that idea.

This reading would make no sense when applied to "(LE) re lei ci cutci"
or "(LE) re ko'a", so these would preserve the meanings "two members of
the trio of shoes", "two members of ko'a". This latter meaning would be
less useful when applied to "re loi ci cutci" -- "two things such that
for each there is a trio of shoes it is a member of" or "two things
such that there is a trio of shoes that each is a member of": here 
there'd be an ambiguity in need of resolution, and neither meaning is
as useful as "two trios of shoes". Furthermore, by eschewing these
meanings in favour of xorxes's, we can uphold what ought to be an
important principle, namely that within a 'gadri complex', only the
outermost PA expresses quantification.

As for lo (o-Kind) and le (e-Kind), outer quantification can either
be over members ("(loi) re lo ci cutci" = 2 members of Mr Trio of Shoes)
or over subkinds ("(loi) re lo ci cutci" = 2 subkinds of Mr Trio of 
Shoes). If over subkinds, then quantification over members of Kinds
can be done by lu'a. If over members, then quantification over subkinds
can be done by a new LAhE-subkind. Le (e-Kind) and lei (e-Group) need
not necessarily be kept separate if quantification of both is over
members.

Summary:

LE PA1 loi PA2 broda
= LE PA1 things each of which is a Group of PA2 broda

LE PA1 lei PA2 broda
= LE PA1 things each of which is a member of a certain Group of PA2 broda.

+ Option A:

LE PA1 lo PA2 broda
= LE PA1 things each of which is a subkind of Mr PA2 Broda.

LE PA1 le PA2 broda
= LE PA1 things each of which is a subkind of a certain Kind (described as
PA2 Broda).

LE PA1 lu'a lo PA2 broda
= LE PA1 things each of which is a member of Mr PA2 Broda.

LE PA1 lu'a le PA2 broda
= LE PA1 things each of which is a member of a certain Kind (described as
PA2 Broda).

+ Option B:

LE PA1 lo PA2 broda
= LE PA1 things each of which is a member of Mr PA2 Broda.

LE PA1 le PA2 broda
= LE PA1 things each of which is a member of a certain Kind (described as
PA2 Broda).

LE PA1 LAhE-subkind lo PA2 broda
= LE PA1 things each of which is a subkind of Mr PA2 Broda.

LE PA1 LAhE-subkind le PA2 broda
= LE PA1 things each of which is a subkind of a certain Kind (described as
PA2 Broda).

+ Option C:

LE PA1 lo PA2 broda
= LE PA1 things each of which is a member of Mr PA2 Broda.

LE PA1 LAhE-subkind lo PA2 broda
= LE PA1 things each of which is a subkind of Mr PA2 Broda.

No e-Kind (le) in the part of system.

LE PA1 lei PA2 broda
= LE PA1 things each of which is a member of a certain thing [which may or
may not be a Kind]

LE PA1 LAhE-subkind lei PA2 broda
= LE PA1 things each of which is a subkind of a certain thing [which may or
may not be a Kind]

--And.